RE: Memory Management question

[Richard Burmeister]

> What is n in memptr[n]?  What about each
> memptr[x], where 1 <= x <= items?

Oops!  I should have said "0 <= x < items".  Hopefully, the idea was clear:
the code he posted did a MemPtrNew() and assigned the result to memptr[n],
ignoring all the other pointers in that array.


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