Interesting... If you draw a arbitrary smooth curve with continuous first order derivative, there is a curvature at any point on the curve, and a radius of curvature associated with that curvature. It means at any point there is an arc of a circle that best describes an infinately small segment of that curve. If the curve happens to be a stright line, the curvature is zero and the radius of curvature is infinite.
Circle is defined as x^2 + y^2 = R^2 in the usual x-y coordinate. Mathematically, if R=0, it is a point; if it is infinite, that's nothing. Max --- Joe Programmer <[EMAIL PROTECTED]> wrote: > --- Michael Glickman wrote: > > > > Well this is just a matter of terminology. > > In fact a line is a circle with zero curvature, > > > > I don't see any way that can be true. What universe are you from? > > Here is a standard definition of a circle: > > A circle is the set of all points in a plane > at a fixed distance from a fixed point in the > plane. The fixed point is called the center > of the circle. The fixed distance is called > the radius of the circle. > > On a line, where is the center? What is the radius? __________________________________________________ Do You Yahoo!? Send FREE video emails in Yahoo! Mail! http://promo.yahoo.com/videomail/ -- For information on using the Palm Developer Forums, or to unsubscribe, please see http://www.palmos.com/dev/tech/support/forums/
