Hi all, I'm using the following code to switch to the network panel and display the 'done' button:
DmGetNextDatabaseByTypeCreator(true, &theSearchState, sysFileTPanel,sysFileCNetworkPanel,true, &cardNo, &dbID); SysUIAppSwitch(cardNo, dbID,sysAppLaunchCmdPanelCalledFromApp, 0); This works fine but when I press the done button my application gets relaunched (i.e. as if it has received a sysAppLaunchCmdNormalLaunch). I know that this is because pressing the done button returns to the last app that was running. But this causes all sorts of problems. I thought I'd be able to get round the problem by handling the sysAppLaunchCmdReturnFromPanel launch code but this doesn't seem to work. Should it (and thus I've made a stupid error somewhere) or is there a better way of doing this ? cheers Steve -- Steve Janaway Aepona (England) Ltd Internet: http://www.aepona.co.uk -- For information on using the Palm Developer Forums, or to unsubscribe, please see http://www.palmos.com/dev/support/forums/
