you can copy a 0-terminated string with StrCopy (it actually only works for such a string). StrCopy will add a 0-byte at the end of the destination string. StrNCopy (the safe version of StrCopy) will not add a 0-byte to the end of destionation, if (and only if) the space for the destination was not enough to copy the whole string + the 0-byte. Therefore if you use StrNCopy use as parameter for the destination size one byte less than the real size is. Then you can add 0-byte as last byte of your destination in any case.
dest[an array big enough for the string + 1 byte]
// this will add a 0-byte at position src[StrLen(dest)]
StrCopy(dest, src);
// but can overwrite your destination, if it wasn't big enough
// this will not overwrite your destination, but it will maybe not add a // 0-byte at the end
StrNCopy(dest, src, sizeof(dest));
// therefore do it on your own
dest[sizeof(dest)-1] = 0;
Henk
Michel.P wrote:
Hi Henk, I thought one couldn't copy a null string using StrCopy(): I tried that before posting my question (but usting '\0' instead of "\0") and it gave me an error, and I believe someone in another post said that you can't StrCopy() null....?--- Henk Jonas <[EMAIL PROTECTED]> wrote:Michel,
if you know its 0-terminated, you can do a StrCopy,
add a "\0" and another StrCopy + "\0" from StrLen()+1 as well. The
thing about MemSet is if you have a chunk of memory (getting from
MemLock or whatever) and you don't know if it is initialized with "\0" at the
beginning, you better do a MemSet with 0x00 to ensure you will have
a 0-terminated string, regardless what you do.
Henk
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