Ed Greenberg wrote:
>> The question was in items. The solution for me, as suggested 
>> by Aaron Ardiri was to divide the height of the list in pixels 
>> by the font height.

Why not just call LstGetVisibleItems() to find out how many items are
visible in the list?  This seems more reliable than assuming the height of
each item is the same as the font height.

Jeff
 





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