HI
you should also allocate a memory for second[0].
try doing this
MemHandle memH;
Char ** second1 = NULL;
UInt16 i;
memH = MemHandleNew (sizeof (Char *) * 15);
second1 = (Char **) MemHandleLock (memH);
if (!second)
{ Give Some Error}
for (i=0; i<15; i++)
{
MemHandle secH;
secH = MemHandleNew (sizeof (Char *));
second1[i] = (Char *) MemHandleLock (secH);
if (!second1[i])
{ error message}
// do whatever you u want to do with second[0]
StrCopy (second1[i], CurrentNode->Product);
}
//And Do not forget to free memory.
//Sample code for freeing the memory
void freeMem ()
{
UInt16 i;
if (second1)
{
for (i=0; i<15; i++)
{
if (second1[i])
MemPtrFree (second1[i]);
}
MemPtrFree (second1);
}
}
--- Sean Charles <[EMAIL PROTECTED]> wrote:
>
> On Saturday, February 8, 2003, at 01:49 PM, burhan
> ahmad wrote:
>
> > can anybody plz tell me why cant i copy to
> second1[0];
> > char **second1;//intitialized as below
> > second1 = (Char **) MemPtrNew(15 * sizeof(Char
> *));
> >
> >
> > StrCopy(second1[0], CurrentNode->product);
> ...get the fire hose ready bubba...
>
> > it gives null string passed error although there
> is char value in
> > product.
> yeah, what about the destination then.....?
>
> After allocating space for your pointers, maybe try
> allocatin some space
> for them to point to. Life may run a little smoother
> after that!
>
> Sean Charles.
>
>
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