No Mark, it seems you missed what I said.
I showed what the expression *does* as written.
And I explained why it's *wrong* as written.
To clear up confusion, here is what the expression *should* be, in order for
it to work as the author really intended:
isMemoFindKey =
event.eType == keyDownEvent
&&
(
(
TxtCharIsHardKey(event.data.keyDown.modifiers,
.data.keyDown.chr)
&&
event.data.keyDown.chr == vchrHard4
)
||
event.data.keyDown.chr == vchrFind
)
See the problem now?
"Mark Wilden" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
>
> ----- Original Message -----
> From: "Chris Antos" <[EMAIL PROTECTED]>
>
>
> > First of all, your operator precedence is messed up -- read up on the
> > precedence of && vs || and add more parentheses to make it explicit what
> > conditions you wanted to test.
> > [...]
> > isMemoFindKey =
> > (
> > (event.eType == keyDownEvent) &&
> > (TxtCharIsHardKey(event.data.keyDown.modifiers,
> > event.data.keyDown.chr)) &&
> > (event.data.keyDown.chr == vchrHard4)
> > )
> > ||
> > (
> > event.data.keyDown.chr == vchrFind
> > )
>
> Actually, this doesn't need any additional parentheses.
>
> isMemoFindKey =
> event.eType == keyDownEvent &&
> TxtCharIsHardKey(event.data.keyDown.modifiers,
> event.data.keyDown.chr) &&
> event.data.keyDown.chr == vchrHard4
> || event.data.keyDown.chr == vchrFind
>
>
>
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