> I'm reading Palm OS Programming Bible. There is the following instructions: > ================ > CtlSetLabel( ctl, LstGetSelectionText( list, 1 ) ); > CtlSetLabel( ctl, "This is a bad idea" ); > ================ > In the book, it said that the 2nd item of 'list' will be overwritten by > "This is a bad idea". However, to my understanding, the 1st instruction > will copy the pointer of 2nd item of 'list' to 'ctl'. Then the 2nd > instruction will copy the pointer (to"This is a bad idea") to 'ctl'. I don't > understand why the 2nd item of 'list' would be overwritten. > > Please give some advice and tell me what's wrong with my concept.
you have mis-read what he is saying :) when you have a pop-up list, you normally have both a control and a list resource. when you make the second call, it will not over-write the list contents - however, it will make the user see that the option they selected is "This is a bad idea" (which, may not be in the list).. to overwrite the contents of the 'list' - you would need to modify the pointer of strings (stringlist) and call the LstSetSelectionText() API call. try the examples.. and, you'll see what i mean. it is sometimes good to use this technique to have a pop-up list that says "Select Item", and, the list contains a bunch of items - when the user selects it, the "Select Item" goes away, and, everyone is happy. --- Aaron Ardiri [EMAIL PROTECTED] CEO - CTO +46 70 656 1143 Mobile Wizardry http://www.mobilewizardry.com/ -- For information on using the Palm Developer Forums, or to unsubscribe, please see http://www.palmos.com/dev/support/forums/
