const char* cat_control[2] = { CAT_CONTROL + '0', '\0' };
although this only works with single digit values ... :-)
Chris
Bob Withers wrote:
You need two levels, i.e.
#define CAT_CONTROL 7
#define STR1(x) #x #define STR(x) STR1(x)
printf("%s", STR(CAT_CONTROL));
Bob
At 11:36 AM 7/25/2003 -0300, you wrote:
Hi,
I have this constant, #define CAT_CONTROL 7
I want to convert CAT_CONTROL to const char * and I don't want to do this:
char cAux[2]; itoa(CAT_CONTROL ,cAux,10);
I try to use a preprocessor operator:
#define STR(x) #x
But that doesn't work, because I obtain "CAT_CONTROL" like result.
Any help would be greatly.
Best Regards, German
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