On December 7, 2001 11:20 am, you wrote:
> Hey ,
> I am facing a problem , i want to find an ASCII character value of an
> integer in my program.How can i do that?
> Kindly reply ASAP.
>
> Best Regards
> Khuram Mir
If it's a UInt8, you can just use it as a character wherever you can use a
character, just typecast it to stop the compiler from complaining. I.e:
Char string[32];
UInt8 num = ' '; // Decimal 32, I believe.
StrPrintF(string, "The number represents: '%c'", num);
In the above example, 'string' now should contain the text:
The number represents: ' '
If you are trying to display, say, a UInt32 creator ID as a four-character
string, you can use the following code:
Char *FourCharInt ( UInt32 value, Char *buffer ) {
Char *ptr;
ptr = (Char *)&value;
StrPrintF ( buffer, "%c%c%c%c\0", ptr[0], ptr[1], ptr[2], ptr[3] );
return buffer;
}
Just copy and paste the above code, rename it to TwoCharInt, and remove two of
the ptr[] references to display the string value of a UInt16.
Hope this helps, and if not, at least it's more publicly available code,
--
Matthew Bevan, Margin Software
- Re-inventing the wheel, every time.
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