Any easy way of doing this other than doing it manually (i.e. going character by character and building up the number)
StrIToH, in the docs.
Oops. Another case of reading quickly but not too thoroughly. Ignore that (useless) advice.
Instead, here's something from RegCode that converts the 1st and last 5 chars of a string into a HEX string, separated by colons, and adds a checksum. You should be able to adapt it pretty easily.
Regards, Steve Mann --- steve-at-slorevo.com Available for Contract Work
unsigned char *regCode(unsigned char *user, Boolean nameOnly)
{
static unsigned char name[11];
static char hex[] = "0123456789ABCDEF";
int len;
int c=0, n=0, idx=0, i;
unsigned char checkSum = 0;len=StrLen((const char *)user);
for(i=0;i<MIN(len,10);i++) {
junk[c++] = hex[user[idx]/16];
junk[c++] = hex[user[idx]%16];
junk[c++] = ':';
name[n++] = user[idx];
checkSum += user[idx++];
if(len > 10 && idx == 5)
idx = len - 5;
} junk[c++] = hex[checkSum/16];
junk[c++] = hex[checkSum%16];
junk[c] = '\0';
name[n] = '\0'; if(nameOnly)
return name;
else
return junk;
}Regards, Steve Mann
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