Matheus, activeSource.FileName
will get you the path to the file. This ought to work for most file readers. os.path.dirname(activeSource.FileName) will get you the directory. HTH, Cory On Sun, Dec 6, 2015 at 11:05 PM, Matheus Viana <[email protected]> wrote: > Hi list. > > I was wondering whether it is possible to determine the folder where the > active source was loaded from in a Python script. > > Thanks, > > *Matheus Viana* > *Postdoctoral Research Employee* > *Developmental and Cell Biology* > *University of California Irvine* > > > > _______________________________________________ > Powered by www.kitware.com > > Visit other Kitware open-source projects at > http://www.kitware.com/opensource/opensource.html > > Please keep messages on-topic and check the ParaView Wiki at: > http://paraview.org/Wiki/ParaView > > Search the list archives at: http://markmail.org/search/?q=ParaView > > Follow this link to subscribe/unsubscribe: > http://public.kitware.com/mailman/listinfo/paraview > > -- Cory Quammen R&D Engineer Kitware, Inc.
_______________________________________________ Powered by www.kitware.com Visit other Kitware open-source projects at http://www.kitware.com/opensource/opensource.html Please keep messages on-topic and check the ParaView Wiki at: http://paraview.org/Wiki/ParaView Search the list archives at: http://markmail.org/search/?q=ParaView Follow this link to subscribe/unsubscribe: http://public.kitware.com/mailman/listinfo/paraview
