On Mon, Feb 2, 2015 at 5:58 PM, Étienne Deparis <[email protected]> wrote:
>
> Hi!
>
> I use intensively pass, which is a clever solution to password
> management. However I miss a feature, which allow me to quickly get
> password information when I know the pass file, but forgot (or don't
> want to remember) its position in the password tree.
>
> Thus, I propose the attached patch, which add an option to the "show"
> command in order to display the content of the first file matching the
> path parameter. Sort of "I'm lucky" thing for my password bucket.
Hi Etienne, List,
I implemented something very similar on my local pass some time ago.
This is a good opportunity to post it to the list. It's only 5 lines
added to the
show function. Please note that the man/documentation is not updated, and that
the code/patch is probably note formatted as it should be.
The attached patch changes the behavior of the show command.
When the argument is a keyword, i.e. text with no "/" in it, it simply tries
to find a single matching password and shows it. It only works if the search
matches a single result.
The normal "show" behaviour is not changed if a path is given as an argument.
There is no need to use an extra option or parameter to trigger the
new functionality.
Examples:
Normal show behavior:
$ pass show private/misc/www.example.com
blabla
login: blibli
Keyword based show behavior:
$ pass show example
blabla
login: blibli
$ pass show example.net
Error: example.net is not in the password store.
This patch is formatted against version 1.6.5.
Regards,
William
--- /usr/bin/pass 2015-02-02 19:53:59.983451348 +0100
+++ /usr/bin/pass_ 2015-02-02 19:38:34.680459331 +0100
@@ -307,6 +307,13 @@
local path="$1"
local passfile="$PREFIX/$path.gpg"
check_sneaky_paths "$path"
+
+ if echo $path | grep -vq "/"
+ then
+ local lines=$(find "$PREFIX" -type f -iname "*${path}*.gpg")
+ [[ $(echo $lines | wc -l) -eq 1 ]] && passfile=$lines
+ fi
+
if [[ -f $passfile ]]; then
if [[ $clip -eq 0 ]]; then
$GPG -d "${GPG_OPTS[@]}" "$passfile" || exit $?
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