Patches item #1068277, was opened at 2004-11-17 16:20
Message generated for change (Comment added) made by akuchling
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Category: Documentation
Group: Python 2.5
>Status: Closed
Resolution: Accepted
Priority: 5
Submitted By: Robert Brewer (aminusfu)
>Assigned to: A.M. Kuchling (akuchling)
Summary: os.path.exists returns False if no permission
Initial Comment:
A single new sentence for os.path.exists description,
which makes it clear that it may return False even if
the path actually exists.
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>Comment By: A.M. Kuchling (akuchling)
Date: 2006-07-29 15:57
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Fred approved this patch, so I've tweaked it a little and committed it. (rev.
50950 on the trunk, 50951 on the release24-maint branch.)
If we want to change the underlying implementation (and hence semantics) of
os.path.exists(), I think that should be a PEP, or at least a separate bug.
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Comment By: Armin Rigo (arigo)
Date: 2004-12-20 09:53
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Actually, what about the following ?
def exists(path):
return os.access(path, os.F_OK)
It returns True on all existing directory entries apart from broken links and
links pointing within unreadable directories.
I don't see any similar nice solution for the more recent os.path.lexists()...
There are cases where the above exists() returns True but the current lexists()
returns False, which is strange because lexists() is supposed to be a more
permissive version of exists().
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Comment By: Armin Rigo (arigo)
Date: 2004-12-20 08:00
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I don't see an obvious way to do it, but shouldn't os.path.exists() try harder
to return the expected answer?
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Comment By: Fred L. Drake, Jr. (fdrake)
Date: 2004-12-05 01:56
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This should be committed on the trunk and release24-maint
branch.
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