<[email protected]> писал(а) в своём письме Fri, 27 Dec 2013 16:28:20
+0400:
On Thu, 26 Dec 2013, Zoltán Herczeg wrote:
I didn't know it is accidental. I thought printing an empty string is
less useful for a testing tool. Perhaps printing the offsets
themselves would be the best.
I have committed a patch that does this:
/(?=ab\K)/+
abcd
Start of matched string is beyond its end - displaying from end to start.
0: ab
0+ abcd
Sorry. But I don't understand why result is 'ab'. I think result must be
''.
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