On Apr 17, 2009, at 11:25 AM, Miller Puckette wrote:
On Fri, Apr 17, 2009 at 11:21:46AM -0400, Hans-Christoph Steiner
wrote:
On Apr 17, 2009, at 6:49 AM, IOhannes m zmoelnig wrote:
Hans-Christoph Steiner wrote:
I am trying to track down the path of loading a new object.
Basically,
where does a class name get tested to see if a .pd_linux needs to
be
loaded or not? For example, if I type [drip], where does it look
to see
whether it needs to load drip.pd_linux?
Right now, I am staring at the top of canvas_objtext() and not
quite
getting it.
hmm, do you want to know when exactly Pd decides whether it already
has
the "drip" objectclass registered or whether it needs t invoke the
loader-mechanism?
an objectclass (or rather: it's name) is basically a method for the
"pd_objectmaker". if it has no method registered for "drip", then it
will fallback to it's anything-method (new_anything), which will
call
the registered loaders and finally tries to open the "drip" as an
abstraction.
mfgasr
IOhannes
Ok, that makes sense now. So where does this registration with
pd_objectmaker happen? That's what I am looking for, but couldn't
find.
.hc
in class_new() -- which is called when the extern is loaded.
cheers
M
Of course, I'd never bridged that gap in my brain before... one last
plea for help: I am trying to figure out a way to look up the
newmethod when I only have a char *classname. I think binbuf_eval()
just executes the newmethod based on the char *classname, but I want
to get the pointer to the newmethod.
.hc
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