That formula should read:
color = ([red] * 65536) + ([green] * 256) + ([blue])
In binary the idea is to shift the 8 'red' bits 16 to the left, then add
8 'green' bits shifted 8 bits, and finally 8 'blue' bits, so in all 24
bits are occupied.
Multiplying the blue value by -1 in the original formula has the effect
of setting the 16 bits to the left of it to 1, so you get different
shades of pure blue.
Martin
Robert Schwarz wrote:
Hi all,
I recently tried writing patches in a text editor (or from scripts) and
had problems getting the color settings right, for bang elements.
There is some documentation at
http://puredata.info/docs/developer/fileformat
with the explanation:
Color: Some graphical elements have color attributes. Per color only
one signed integer value is stored that contains the three 8-bit
color components (RGB). Formula to calculate color attribute values:
color = ( [red] * -65536) + ( [green] * -256) + ( [blue] * -1)
Where [red], [green], [blue] obviously represent the three color
components, their values range from 0 to 255. They apply to the
attributes [background color], [front color], [label color] of
various elements.
I tried that, but it didn't work. Instead of showing the whole spectrum
I just got different shades of blue. Also, when I opened one of my
handwritten patches in PureData, looked at the color settings and saved,
the resulting numbers changed. I assume that some kind of rounding is
happening, and colors are actually saved in lower resolution.
Do you have any ideas?
Also, my application is a 13x13 button matrix, each triggering different
chords via MIDI. The buttons should be color coded. Obviously, it's too
much work setting all colors individually and I might want to create
several of these patches with different colors.
Maybe there is another obvious solution I didn't see.
Any help is appreciated!
(I'm using standard pd 0.42_5 on Arch Linux, but this shouldn't make a
difference.)
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