The implementation of signal_setoutchans() looks good to me! There is
indeed no danger of breaking signal aliasing. Since the dummy output
signals are "empty" (s_nchans = 0), they are allocated from the "borrow"
free list and not from the "real" free list. Nice :-)
I think signal_setoutchans() is quite elegant and pleasant to use. Thanks!
Christof
On 25.01.2023 18:04, i...@christofressi.com wrote:
> yep - and in fact I need length to be correct, otherwise there's no
easy way
to get it.
That's what I was hinting at :-)
I find the empty signal quite elegant. Only s_nchans and s_vec are 0,
the rest stays intact. This makes sense conceptionally because
s_nchans * s_length is still 0.
> sp[2] = signal_makemultichannels(sp[2], outchans);
I like this! I think the naming is very descriptive.
Christof
Am 25.01.2023 17:39 schrieb Miller Puckette via Pd-dev
<pd-dev@lists.iem.at>:
On Wed, Jan 25, 2023 at 05:34:48PM +0100, IOhannes m zmoelnig wrote:
> conceptually, i like this; though i would suggest "channels=0;
length=64"
> (or whatever).
>
yep - and in fact I need length to be correct, otherwise there's
no easy way
to get it.
> > and instead of (for example)
> > sp[2] = signal_swapforchans(sp[2], outchans);
> > you'd just write
> > signal_setchans(sp[2], ouchans).
>
> hmm, wouldn't that modify the t_signal* struct that sp[2] points
to,
> potentially breaking the reuse? (so it ought to be
"signal_setchans(&sp[2],
> outchans)")
>
I _think_ it works just to pass sp[2] in place - it's a (t_signal
*) and
all that's needed is to alter member element s_vec, s_nchans.
> and i find the "swapforchans" slightly confusing (which fo(u)r
channels are
> being swapped? the actual swapping is done by re-assigning a new
value to
> sp[2]).
> so how about:
> sp[2] = signal_makemultichannels(sp[2], outchans);
>
so this would become moot.
>
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