On 12/05/2007, at 11.58, Kim Taylor wrote:

> For example: lets say there is an input signal to the explicitly
> defined sequence of delwrite~ - delread~ - output
> At t=0 the sample starts playing. Surely only until t=64 can a block
> be written by delwrite~ (immediately), and read (immediately) by
> delread~?

If I understand this right, then immediately here means the the  
sample from t=0 is there/available immediately as opposite to having  
to wait till t=0+blocksize.

I might of cause be all wrong. Just testing knowledge gained at a in  
scope similar thread.

Best,
Steffen

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