Derek Holzer escribió:
What if you bang a [f $1] and send it to [expr size("$1foo")]?

Likewise with "bang"--->[f $0]--->[expr size("$0foo")]?

The problem is you cannot create [expr size("$1foo")] in the first place (nor with $0): it gives the syntax error at creation time and refuses to create.

If you could, then you wouldn't need the [f $0] (the expression doesn't depend on the input)....

--
Matteo Sisti Sette
[email protected]
http://www.matteosistisette.com

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