Excellent, I've been making tons of progress! Now I'm wondering if there's a way to retrieve a single column from a [#many] object...? I have been trying a for++ loop to iterate through the rows of a specified column but it's not working very well and I can only do that via a [#store] object...
Thanks so much!! ±t3db0t On Jan 28, 2011, at 3:34 PM, Mathieu Bouchard wrote: > On Fri, 28 Jan 2011, Tedb0t wrote: > >> Awesome! I started this patch (basically a drum sequencer interface with >> recallable banks), but not sure why [#store] isn't working here: > > It's because [#many] contains a [#store] that needs to have a 2-dimensional > grid in it, and [#many] doesn't check that you give it such a grid, and by > default, [#store] contains a 0-dimensional grid whose contents is a single 0. > >> Perhaps the [#store]s need to be initialized with the right dimensions? Not >> sure how to do that... > > A grid literal such as «6 8 #» will expand to a 6×8 grid of zeroes, if you > pass it as a single argument where a grid is expected (using parentheses) or > as a list-message to a grid-inlet. > > for example, [#store (6 8 #)] > and to clear the contents, have a «6 8 #» messagebox. > > (I use «» to quote a list or messagebox contents in email. It's not part of > GridFlow.) > > _______________________________________________________________________ > | Mathieu Bouchard ---- tél: +1.514.383.3801 ---- Villeray, Montréal, QC _______________________________________________ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list
