Hi all - I believe the general formula for Hann is to divide by (3/8 * overlap * window size).
this assumes that the inout and output are both Hann windowed, therefore you're really dindowing by the square of the Hann window whose average over N points is 3/8. cheers Miller On Fri, Oct 12, 2012 at 05:44:20PM -0500, Charles Henry wrote: > On Fri, Oct 12, 2012 at 4:59 PM, Alexandre Torres Porres > <[email protected]> wrote: > > hi there, in pd's examples, we need to divide by (3/2 * window size) in a 4 > > overlap on a hann window. > > > > what about other overlaps, what is the normalizing factor? > > > > and how about other windows? > > > > I looked for this info on books and google and stuff, found nothing. > > > > Engineers, please help. > > > > thanks > > Alex > > I'm not exactly sure why it's used either. If you were using a > overlap of 2 and used hann windows that cover each block, you would > get back the exact signal after applying overlap-and-add with no > additional normalization. > > So, for the same scheme and overlap 4, it stands to reason that you'd > only divide by 2 and recover the original signal as well. > > What's the window size like relative to the block size? same/different? > > Some other engineer--please help. > > Chuck > > _______________________________________________ > [email protected] mailing list > UNSUBSCRIBE and account-management -> > http://lists.puredata.info/listinfo/pd-list _______________________________________________ [email protected] mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list
