Hi Alexandre, This is the online tool: http://kmt.hku.nl/~pieter/cgi-bin/resp/nph-PZT.cgi.
It starts with an example and every time you refresh the page it gives you a new one. If you scroll down there's a link that tells you how the coefficients were calculated, e.g.: 2 zeros give 3 coefficients: *a0* = G *a1* = -G(Z0 + Z1) *a2* = G(Z0*Z1) 2 poles give 3 coefficients: *b0* = 1 *b1* = -(P0 + P1) *b2* = (P0*P1) The linear difference equation is derived from these as you can see. Regards, --Funs On Tue, Sep 24, 2013 at 7:36 AM, Alexandre Torres Porres <[email protected]>wrote: > for what i see, it's not some sort of straight formula, right? seems a bit > more complicated than that. > > cheers > > > 2013/9/23 Funs Seelen <[email protected]> > >> On Mon, Sep 23, 2013 at 5:35 PM, Alexandre Torres Porres < >> [email protected]> wrote: >> >>> >>> thanks, here's a pic of what I have so far >>> >>> >>> https://fbcdn-sphotos-g-a.akamaihd.net/hphotos-ak-prn1/11212_10151872996046683_1825736206_n.jpg >>> >> >> Cool. >> >> >>> >>> > For extra inspiration you could have a look at PoZeTools >>> >>> It sure does look like what I need. Thanks. But extracting what I need >>> to know about the math of converting from coordinates to coefficients was >>> just over my head :P unfortunately, sorry. >>> >>> I was hoping for something simpler, like just the operations needed. If >>> the info is in code, I need it to more explicit. I'd really appreciate if >>> anyone knows how to read from this and just points it out for me so I can >>> put it in a patch. >>> >>> I'm assuming it's rather simple math >>> >> >> I remember I once learned how to do this but never repeated the practice. >> If I find time to do that I would gladly try to figure it out again, but if >> someone more experienced feels the urge to chime in before that time I >> would be very happy too :). >> > >
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