I often create abstractions using $0 as an argument, such as [line-seg
1 2 $0], and then $3 in the abstraction is the same as $0 in the parent.
That's a common pattern, yes. Your example doesn't contradict my point,
though: because [line-seq] can't access the parent $0 *), you have to
pass it from the outside.
if you really want, you can export the individual $0-values to a text
file to be read in the command line.
Please don't. $0 are potentially different every time you open the
abstraction. Currently, they start with 1000 and increment
monotonically, but this is really an implementation detail that you
shouldn't rely upon.
Christof
*) with [iemguts/canvasdollarzero] you can
On 12.12.2021 13:28, João Pais wrote:
you can send something to $0-xxx variables, but you should only do it
if it makes sense.
I often create abstractions using $0 as an argument, such as [line-seg
1 2 $0], and then $3 in the abstraction is the same as $0 in the
parent. if you really want, you can export the individual $0-values to
a text file to be read in the command line. But is it necessary?
$0 is a unique number that only the abstraction itself knows about.
Typically you use it to keep things local. Just like you can't send a
message to [r $0_msg] from another patch, you can't do it with
"-send", either.
Just create a new patch, put your abstraction there and add a
[receive foo] (without $0!) that will send the appropriate message to
the abstraction. Now you can do
$ pd -nogui -send "foo 1"
Christof
On 12.12.2021 12:16, padovani wrote:
Hi,
I have a patch like
[r $0_msg]
|
[print]
And would like to run Pd from command line (-nogui -send "....") and
send something to the receive object.
How can I pass the '$0_msg' name in a way bash and Pd understand it?
Have tried different combinations of quotes and bars, but nothing
works... :/
thanks!
josé
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