I always thought that this is actually default behavior of the pdl
constructor.
developer@devbox:~$ perl -e 'use PDL; print pdl([[1],[1,2],[1,2,3],[1]])'
[
[1 0 0]
[1 2 0]
[1 2 3]
[1 0 0]
]
On Sat, Oct 28, 2017 at 12:33 PM, Adam Russell <[email protected]> wrote:
> I have a data file in which each row has a variable number of columns. I
> am reading this file into a regular Perl array first in order to do some
> basic pre-processing of the data. I then am presently adding 0s to pad each
> row to be as long as the longest row and so I have a rectangular array. I
> then pass the array to pdl() and things seem OK.
>
> Is there a way to do this easier though? To skip writing my own loop to
> pad the array first? That is, a way to take the irregularity shaped array
> and have pdl make it rectangular for me?
>
> ------------------------------------------------------------
> ------------------
> Check out the vibrant tech community on one of the world's most
> engaging tech sites, Slashdot.org! http://sdm.link/slashdot
> _______________________________________________
> pdl-general mailing list
> [email protected]
> https://lists.sourceforge.net/lists/listinfo/pdl-general
>
>
------------------------------------------------------------------------------
Check out the vibrant tech community on one of the world's most
engaging tech sites, Slashdot.org! http://sdm.link/slashdot
_______________________________________________
pdl-general mailing list
[email protected]
https://lists.sourceforge.net/lists/listinfo/pdl-general
