Hi Luis, is it not doing ci() + $x (expected behaviour) rather than ci( +$x) ?
Ingo On 07.03.21 23:42, Luis Mochan wrote:
Thus, ci+$x is interpreted as ci(+$x) which actually assigns complex i to each element of $x if $x is a complex pdl. If $x is real, then it assigns 0 (I guess it type-converts i though its real part).
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