Not really. It doesn't tell you the actual difference that he's looking for but the math is simple if you have a calculator, (I'd hate to do square roots by hand these days, I can't remember any techniques).
Find the diagonal of each frame, simple using sqrt(a^2 + b^2) = c then divide the diagonal of the larger frame by the smaller which is how everyone seems to do this. In this case it's about figuring a 60mm x 60mm frame for traditional film and a 36.7mm x 49mm from Hassalbads spec sheet you get 1.38 close enough for marketing purposes. Jens Bladt wrote: >I believe you may find the answer here: >http://www.jensbladt.dk/Images/Focal-length-multiplier-web.jpg >Regards >Jens > >Jens Bladt >http://www.jensbladt.dk >+45 56 63 77 11 >+45 23 43 85 77 >Skype: jensbladt248 > >-----Oprindelig meddelelse----- >Fra: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] vegne af Peter >Fairweather >Sendt: 30. september 2006 11:30 >Til: Pentax-Discuss Mail List >Emne: Re: OT So no one finds this interesting? > > >I wonder what the multiplier on the standard Hasselblad lenses is? >Could make the APS multiplier of 1,5 look generous! > >Peter > >-- >PDML Pentax-Discuss Mail List >[email protected] >http://pdml.net/mailman/listinfo/pdml_pdml.net >-- >No virus found in this incoming message. >Checked by AVG Free Edition. >Version: 7.1.407 / Virus Database: 268.12.10/459 - Release Date: 09/29/2006 > >-- >No virus found in this outgoing message. >Checked by AVG Free Edition. >Version: 7.1.407 / Virus Database: 268.12.10/459 - Release Date: 09/29/2006 > > > > -- Things should be made as simple as possible -- but no simpler. --Albert Einstein -- PDML Pentax-Discuss Mail List [email protected] http://pdml.net/mailman/listinfo/pdml_pdml.net
