On Mon, Sep 19, 2011 at 10:50 PM, Larry Colen <[email protected]> wrote:
>>
> Diffusion or diffraction?
> It was my understanding that diffraction happens at any opaque edge within a
> range that is determined by the wavelength.  Therefore the larger the
> aperture the smaller the percentage of it that will be subject to the
> effects of diffraction.
>
> f/64 on a 320 mm lens would be an aperture of 5mm, which would be the same
> as f/10 on a 50mm lens or f/8 on a 40mm.
>
> I suppose that it's possible that the angle of incidence of the light beams
> hitting the aperture could affect the amount of diffraction, and therefore
> it's not a linear function that diffraction becomes a problem with apertures
> of 2mm or smaller in diameter.
>
> It's also been roughly 30 years since I took a course in either physics, or
> field equations, so I could be completely off base.

Aperture values are ratios, not absolute values.  f/64 on LF is going
to be a different size than f/64 on 35mm.

On a 320mm lens, f/64 has an aperture diameter of 5mm.  On a 50mm
lens, f/64 would have an aperture diameter of .78mm.  (This doesn't
account for the fact that the aperture blades aren't necessarily at
the nodal point in a lens, and you are talking about a simple lens,
reality is a bit messier.)

Your numbers are completely wonky.

>
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> Larry Colen [email protected] (from dos4est)
>
>
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