Well, Since the apparent motion of the sun is constant, all the photographer had to do was take a picture every X minuites. He took 18 frames (counting the number of suns in the picture), and the eclipse in San Fransiscio took T time. All he had to do to find X is simple math: T/18 = X
Calculating exposure must have been tough though . . . he had to decide what the exposure should be, then divide it up so that all 18 exposures equalled the final exposure he needed. IL Bill smcforme wrote: > > I wonder what calculations the photographer used to get the nearly pefect spacing >of each exposure? > "Daniel J. Matyola" <[EMAIL PROTECTED]> wrote: There is a great photo of this >week's eclipse on today's Astonomy Picture of > the Day: > > http://antwrp.gsfc.nasa.gov/apod/astropix.html > > -- > Daniel J. Matyola mailto:[EMAIL PROTECTED] > Stanley, Powers & Matyola mailto:[EMAIL PROTECTED] > Suite203, 1170 US Highway 22 East http://danmatyola.com > Bridgewater, NJ 08807 (908)725-3322 fax: (908)707-0399 > - > This message is from the Pentax-Discuss Mail List. To unsubscribe, > go to http://www.pdml.net and follow the directions. Don't forget to > visit the Pentax Users' Gallery at http://pug.komkon.org . > Sign-up for Video Highlights of 2002 FIFA World Cup > - > This message is from the Pentax-Discuss Mail List. To unsubscribe, > go to http://www.pdml.net and follow the directions. Don't forget to > visit the Pentax Users' Gallery at http://pug.komkon.org . - This message is from the Pentax-Discuss Mail List. To unsubscribe, go to http://www.pdml.net and follow the directions. Don't forget to visit the Pentax Users' Gallery at http://pug.komkon.org .
