A PEG parser should never match anything with this rule, because to
match the symbol a you must first attempt to match the symbol a. (If
your parser matches anything with this rule, it isn't a PEG parser.)
Why don't you rewrite your rule as follows?
a <- ('a' / 'b')* 'a' / 'b'
Best,
- Francisco Mota
On 1/31/12, Ondřej Bílka <nel...@seznam.cz> wrote:
> What your parser does on following rule:
> a = a* 'a' | 'b'
> say on string ababbba
>
> --
>
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