Post   : Peirce's 1870 “Logic Of Relatives” • Comment 12.3
http://inquiryintoinquiry.com/2014/06/12/peirces-1870-logic-of-relatives-%e2%80%a2-comment-12-3/
Posted : June 12, 2014 at 4:32 pm
Author : Jon Awbrey

Peircers,

We now have two ways of computing a logical involution that raises a dyadic 
relative term to the
power of a monadic absolute term, for example, l^w for “lover of every woman”.

The first method operates in the medium of set theory, expressing the 
denotation of the term l^w as
the intersection of a set of relational applications:

• l^w  =  ⋂_{x ∈ W} L ⋅ x

The second method operates in the matrix representation, expressing the value 
of the matrix *L*^*W*
with respect to an argument u as a product of coefficient powers:

• (*L*^*W*)_u  =  ∏_{v ∈ X} *L*_{uv}^*W*_v

Abstract formulas like these are more easily grasped with the aid of a concrete 
example and a
picture of the relations involved.

Example 6
=========

Consider a universe of discourse X that is subject to the following data:

• X  =  {a, b, c, d, e, f, g, h, i}

• W  =  {d, f}

• L  =  {b:a, b:c, c:b, c:d, e:d, e:e, e:f, g:f, g:h, h:g, h:i}

Figure 55 shows the placement of W within X and the placement of L within X × X.

Figure 55.  Bigraph Representation of W ⊆ X and L ⊆ X × X
☞http://inquiryintoinquiry.files.wordpress.com/2014/06/lor-1870-figure-55.jpg

To highlight the role of W more clearly, the Figure represents the absolute 
term “w” by means of the
relative term “w,” that conveys the same information.

Computing the denotation of l^w by way of the set-theoretic formula, we can 
show our work as follows:

• l^w  =  ⋂_{x ∈ W} L ⋅ x  =  L ⋅ d  ∩  L ⋅ f  =  {c, e} ∩ {e, g}  =  {e}

With the above Figure in mind, we can visualize the computation
of (*L*^*W*)_u = ∏_{v ∈ X} *L*_{uv}^*W*_v as follows:

1.  Pick a specific u in the bottom row of the Figure.

2.  Pan across the elements v in the middle row of the Figure.

3.  If u links to v then *L*_{uv} = 1, otherwise *L*_{uv} = 0.

4.  If v in the middle row links to v in the top row
    then *W*_v = 1, otherwise *W*_v = 0.

5.  Compute the value *L*_{uv}^*W*_v = (*L*_{uv} ⇐ *W*_v)
    for each v in the middle row.

6.  If any of the values *L*_{uv}^*W*_v is 0
    then the product ∏_{v ∈ X} *L*_{uv}^*W*_v is 0,
    otherwise it is 1.

As a general observation, we know that the value of (*L*^*W*)_u goes to 0 just 
as soon as we find a
v ∈ X such that *L*_{uv} = 0 and *W*_v = 1, in other words, such that (u, v) ∉ 
L but v ∈ W.  If
there is no such v then (*L*^*W*)_u = 1.

Running through the program for each u ∈ X, the only case that produces a 
non-zero result is
(*L*^*W*)_e = 1.  That portion of the work can be sketched as follows:

• (*L*^*W*)_e = ∏_{v ∈ X} *L*_{ev}^{*W*_v} = 0^0 ⋅ 0^0 ⋅ 0^0 ⋅ 1^1 ⋅ 1^0 ⋅ 1^1 
⋅ 0^0 ⋅ 0^0 ⋅ 0^0  =  1

Regards,

Jon

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