On Sat, 2005-07-02 at 08:55 +0200, demerphq wrote:
> The entire basis of computer science is based around the idea that if
> you do the same operation to two items that are the same the end
> result is the same. Without this there is no predictability. No
> program could ever be expected to run the same way twice.
Throw in some sort of external state and you have exactly that.
Perhaps the name of is_deeply() is misleading, but I don't understand
why the argument about whether container identity should matter to the
function is so important. I expect the following test to pass:
my $a = \1;
my $b = \1;
is_deeply( $a, $b );
Should it not? The values are the same, as are the types of the
containers, but the containers are different.
-- c
