I know that was my inadvertent mistake. I was looking for floating point value conversion, that you have rightly pointed out to below. Thank you and Peter for the useful solutions. It will work for me.
Thank you all! perdeep Perdeep K. Mehta, PhD Group Leader, Bioinformatics Hartwell Center for Bioinformatics & Biotechnology St. Jude Children's Research Hospital Memphis, TN 38105-2794 Tel: 901-495 3774 http://www.hartwellcenter.org -----Original Message----- From: Bruce Hudson [mailto:[EMAIL PROTECTED] Sent: Friday, February 27, 2004 3:23 PM To: Mehta, Perdeep Subject: Re: [Perl-unix-users] conversion between exponential and corresponding > I need help to convert an exponential value such as 10e-5 to its > integer value and vice versa in a perl script. I have to confess I am not sure precisely what you are looking for. Normally where expressing numeric values in an exponential format the mantissa is in the range [1, 10). By "10e-5" do you actually mean "10 * 10^(-5)" or just "10^(-5)". In either case, since the value is less than 1, its "integer value" is 0. Given that converting to an integer is not a 1:1 function, the whole concept of "vice versa" becomes a bit iffy. Assuming that all you want is the simplest case of switching between decimal and exponential notations is a simple matter of using "printf" or sprintf. $number = sprintf ('%d', $value); # 10e-5 -> 0 $number = sprintf ('%f', $value); # 10e-5 -> 0.000100 $number = sprintf ('%e', $value); # 10e-5 -> 1.000000e-04 Based on exactly what you are looking for you will have to play with these a bit but they should give you what you are looking for. -- Bruce A. Hudson | [EMAIL PROTECTED] UCIS, Networks and Systems | Dalhousie University | Halifax, Nova Scotia, Canada | (902) 494-3405 _______________________________________________ Perl-Unix-Users mailing list [EMAIL PROTECTED] To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
