Hi Lixin,
To make it work, instead of using "$ARGV[0]"
You may want to try this:
my $command_line = shift(@_);
Phil
--- "Cai, Lixin (L.)" <[EMAIL PROTECTED]> wrote:
> Now I am meeting the problem: my codes is like:
>
> **************************************************
> $ldapsearch="/usr/bin/ldapsearch";
> my $command = "$ldapsearch -x -LLL -h
> \"cds2.ford.com\" -b \"ou=People,
> o=Ford,c=US\" \"uid=$login\" uid fordUNIXid";
> print "print A ---------- $command";
> @verifyinfo = ldapsearch_result ($command);
>
> sub ldapsearch_result
> {
> my $command_line = $ARGV[0];
> print "print B --------- $command_line\n";
>
> }
> ************************************************
>
> Print A I got:
>
> /usr/bin/ldapsearch -x -LLL -h "cds2.ford.comi" -b
> "ou=People,
> o=Ford,c=US" "uid=ldapdb3" uid fordUNIXid
>
> Print B I got nothing
>
> I do not understand that I have content in $command,
> why I get not get
> it in the method? I am working on linux.\
> Could anyone tell me why?
>
> Thanks a lot in advance!!!!
>
> Lixin
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