Try something like this:
use Cwd;
my $starting_dir = getcwd();
$file = GUI::GetOpenFileName(...
open (FILE , ">$starting_dir/datafile.txt");
You could also do call 'chdir $starting_dir;' before doing the open, however
this probably not does not work if the user changes to a different drive
letter.
Indy Singh
IndigoSTAR Software -- www.indigostar.com
----- Original Message -----
From: "christopher sagayam" <[EMAIL PROTECTED]>
To: <perl-win32-gui-users@lists.sourceforge.net>
Sent: Monday, January 15, 2001 4:23 AM
Subject: [perl-win32-gui-users] GUI::GetOpenFileName and current directory
of perl script
> sub button1_tab1_Click {
> $file = GUI::GetOpenFileName(
> -owner => $W,
> -directory => "C:\\",
> -title => "Location of ",
> -file => $file,
> );
> open (FILE , ">./datafile.txt")
> print FILE $file;
> close(FILE)
> }
>
>
> Now I am intending to do this
>
> 1) Store the full path of the openend file to a file "datafile.txt"
> 2) I have used ./datafile.txt assuming that the file will get stored in
the
> SAME folder as that of my PERL SCRIPT
>
> BUT
>
> when I open the file dialog and choose a file say
"D:\mywork\pages\one.html"
>
> the datafile.txt gets written in D:\mywork\pages\
>
> when I open the file dialog and choose a file say "C:\important\rdf.exe"
>
> the datafile.txt gets written in C:\important\
>
> my perl script is all along at
>
> E:\perlscripts\
>
> SO how do I achieve my objective
>
> chris
>
>
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> Perl-Win32-GUI-Users@lists.sourceforge.net
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>
