incorrect!

chomp $word;

not

$word =~ chomp $word ;

> -----Original Message-----
> From: Bellenger, Bruno (Paris) [SMTP:[EMAIL PROTECTED]]
> Sent: 15/03/2001 12:29
> To:   [EMAIL PROTECTED]
> Subject:      RE: Beginner's problems
> 
> 
> To stay closer to your code, this works : 
> 
> open(IN, "words.txt");
> while(<IN>){
> $word = $_ ;
> $word =~ chomp $word ;
> print "$word and $word\n";
>      }
> 
> 
> The way you did it assigned chomp's return code to $word, 
> not the content of $_
> 
> To avoid this, you must write 
> 
> $word =~ chomp $word ;
> and not 
> $word  =  chomp $word ;
> 
> 
> _____________________________________________
> Bruno Bellenger
> Sr. Network/Systems Administrator 
> 
>       -----Original Message-----
>       From:   BP Jonsson [SMTP:[EMAIL PROTECTED]]
>       Sent:   mercredi 14 mars 2001 14:03
>       To:     [EMAIL PROTECTED]
>       Subject:        Beginner's problems
> 
>       Hi,
> 
>       I'm a Perl beginner who has problems with things that according to
> the 
>       literature should be quite straightforward.  Suppose that I have
> this program:
> 
>            open(IN, "words.txt");
>            while(<IN>){
>                $word = chomp;
>                print "$word and $word\n";
>            }
> 
>       If I the file "words.txt" contains the three lines
>            fred
>            barney
>            dino
>       then this program should print out
>            fred and fred
>            barney and barney
>            dino and dino
> 
>       But all I get is a single digit "1"!
> 
>       WTH is going on?
> 
>       TIA,
> 
>       /BP 8^)>
>       --
>       B.Philip Jonsson mailto:[EMAIL PROTECTED] (delete X)
>       
> 
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