open (FILE, 'input.txt'); while (<FILE>) {s/\s*//g; $output.=$_.'|';} close (FILE); chop $output; print $output;
where input.txt is something like: line1\n line2 \n line3\t\t\n line4\n line5 \t \n
script removes all possible sorts of "white spaces" and linefeds.
then $output is: line1|line2|line3|line4|line5
Viktoras
[EMAIL PROTECTED] wrote:
Hi all,
Here is the script I finally came up with. For some reason I need to find \n within "context" i.e. possible surrounding white spaces and \n.
Daniel
--
my $outputFile = "Out_input.txt";
open (INPUTFILEHANDLE, "input.txt"); open (OUTPUTFILEHANDLE, ">". $outputFile);
$/ = undef; $theFile = <INPUTFILEHANDLE>;
# remove all trailing \n $theFile =~ s/(\s{0,})(\n{1,})/ /g;
# add to each end of field delimiter a \n $theFile =~s/}~/}~\n/g;
# add to each end of record delimniter a \n $theFile =~s/\|/\|\n/g;
# remove trailing spaces after a \n $theFile =~ s/\n(\s{1,})/\n/g;
print OUTPUTFILEHANDLE $theFile . "\n";
close OUTPUTFILEHANDLE; close INPUTFILEHANDLE;
exit 0;
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