On 4/18/05, Lloyd Sartor <[EMAIL PROTECTED]> wrote: > Jerry Kassebaum wrote on 04/17/2005 06:56:29 AM: > > > > > $x=10; > > > > $x=$x++; > > > > print "$x\n"; > > The first result ($x=10) puzzles me. Are not the $x on the LHS and RHS > refering to the same scalar? I would think that $x would be assigned the > value of $x (10), and then be post-incremented, resulting in 11.
1. The current value of $x is stored in register "foo" 2. The current value of $x is incremented by 1, then stored back in $x 3. The contents of register "foo" is stored in $x -- pDale _______________________________________________ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
