On UNIX you have to escape the whitespace, e.g.
/this path/has spaces
would become
/this\ path/has\ spaces
The expression
$path_elem =~ s{(\s)}{\\$1}gio;
should do the trick.
Note that I used {} delimiters (i.e. s{}{}) to make it clearer, since
the data itself contains /s and someone might get confused that a / was
part of the match or substitution, rather than a delimiter. But you
still could use s///, if you prefer. Also, \\ is necessary in the
substituion value, since \ itself is a metacharacter in a regex.
Cheers,
Richard
Cai, Lucy (L.) wrote:
Hi All,
I am meeting a problem on a regular expression.
My code is like:
$path_elem = "$ENV{'CLEARCASE_PN'}";
The return value of $path_elem is either
$path_elem = /ccstore/test/test.pl
Or $path_elem = /ccstore/test 1/test 1.pl # there is a space in the
path name including the file name too
There is no rule whether there is a space in the path name or not. How
can I handle it in regular expression, because when I pass the value
$path_elem to a function, if there is a space in the path name, it will
treat it 2 file path name, instead of one.
I used the following code
$path_elem = "\"$ENV{'CLEARCASE_PN'}\"";
It works fine for windows, but does not works fine on unix.
I really appriciate your great help.
Thanks
Lucy
-
*** Richard A. Wells, [EMAIL PROTECTED], +1.978.371.7425
*** Reality And Wonder, http://www.raw.com/
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