Jan Dubois sent on Thu, 27 Oct 2005 15:42:35 -0700:
> On Thu, 27 Oct 2005, Suresh Govindachar wrote:
>> Hello,
>>
>> When a .bat file with just the line: cd c:\some\where
>> is executed from the Windows cmd shell, then when the
>> .bat file terminates, the directory of the shell would
>> have changed to c:\some\where.
>>
>> How do I get the same effect after running a perl
>> script?
>>
>> (See http://www.xs4all.nl/~waterlan/ for a more complex
>> shell change directory program.)
>
> This can't be done directly, as an application cannot
> modify the parent processes environment. It works for
> .bat files because they are being executed by the shell
> and not run separately.
>
> The closest you can get is having your Perl script write a
> batch file and then call that after the script returns.
> Something like:
>
> del c:\temp\change_env.bat 2>nul
> perl my_script.pl
> if exist c:\temp\change_env.bat call c:\temp\change_env.bat
Thanks Jan -- you got me thinking and I have a nifty solution
(at least for Windows XP's cmd):
The perl file is essentially:
# file the_directory_figure_outer.pl
print 'c:\some\where';
The batch file is essentially:
rem file easy_cd.bat
@for /F "usebackq" %%i IN (`perl the_directory_figure_outer.pl`) DO
@cd %%i
(Preceding should be all in one line.)
Then just run easy_cd.bat and it will change the cmd shell's
directory to whatever was printed by the perl script!
(I have tested this scheme and it works; so if it doesn't work
for you, there must be a typo somewhere.)
--Suresh
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