Hamish Moffatt wrote:
> If you just want to trim spaces, something like
>
> $var =~ s/\s*?(\S)/$1/;
>
> should do the trick. No doubt there are better ways.
The canonical answer (listed, e.g., in `perldoc -q "strip blank space"`),
is:
$var =~ s/^\s+//;
and for end:
$var =~ s/\s+$//;
If you want both left and right trimmed, it's faster (it says) to do the
above two, rather than trying to combine them into one regex. And \s+ is
better than \s* because it won't have to do any work if there isn't any
blank space at the beginning or end.
Cheers,
Philip
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