I think this is not a bug but the result of angle brackets quoting, which creates allomorphs:. It is even documented:
https://docs.perl6.org/language/glossary#index-entry-Allomorph Hope this helps. > On 27 Nov 2016, at 00:47, brian d foy (via RT) <perl6-bugs-follo...@perl.org> > wrote: > > # New Ticket Created by "brian d foy" > # Please include the string: [perl #130184] > # in the subject line of all future correspondence about this issue. > # <URL: https://rt.perl.org/Ticket/Display.html?id=130184 > > > > Adapted from the Stackoverflow answer at: > http://stackoverflow.com/a/40824226/2766176 > > I'm using moar (2016.10) on macosx (10.10.5) darwin (14.5.0) (These > variables are quite nice!) > > This came out of a problem I had with set membership. It turns out > that the way you make the set matters, and the way you make the > candidate member matters. In my case, there's a bug with angle-bracket > word quoting. > > I used the [angle-brackets form of the quote > words](https://docs.perl6.org/language/quoting#Word_quoting:_qw). The > quote words form is supposed to be equivalent to the quoting version > (that is, True under `eqv`). Here's the doc example: > > <a b c> eqv ('a', 'b', 'c') > > But, when I try this with a word that is all digits, this is not equivalent: > > $ perl6 >> < a b 137 > eqv ( 'a', 'b', '137' ) > False > > But, the other forms of word quoting are! > >> qw/ a b 137 / eqv ( 'a', 'b', '137' ) > True >> Q:w/ a b 137 / eqv ( 'a', 'b', '137' ) > True > > The angle-bracket word quoting uses > [IntStr](https://docs.perl6.org/type/IntStr): > >> my @n = < a b 137 > > [a b 137] >> @n.perl > ["a", "b", IntStr.new(137, "137")] > > Without the word quoting, the digits word comes out as [Str]: > >> ( 'a', 'b', '137' ).perl > ("a", "b", "137") >> ( 'a', 'b', '137' )[*-1].perl > "137" >> ( 'a', 'b', '137' )[*-1].WHAT > (Str) >> my @n = ( 'a', 'b', '137' ); > [a b 137] >> @n[*-1].WHAT > (Str)
