El sáb., 6 oct. 2018 a las 12:16, ToddAndMargo via perl6-users (< perl6-us...@perl.org>) escribió:
> On 10/6/18 2:01 AM, JJ Merelo wrote: > > I don't know exactly what you mean by a reference pointer. If you mean a > > pointer, there's no such thing as a pointer, although there is some way > > to represent pointers in the NativeCall interface (which is properly > > Rakudo) https://docs.perl6.org/language/traits#index-entry-CPointer. > > There are no references either, as such. You can bind a variable to > > another, but there's no special syntax for that. > > > > -- > > JJ > > Hi JJ, > > This is what they look like in Perl 5: > > sub GetOldRev ( $$$$$$ ) { > # Incomming: > my $Extension = $_[1]; > my $WorkingDirectory = $_[2]; > my $CallingFunction = $_[3]; > > # Outgoing. Note: these are reference pointers to > # the calling variables > # do not pass constants ("") to them > > my $BaseTagPtr = \$_[0]; > my $OldRevPtr = \$_[4]; $$OldRevPtr = -9999; > my $OldFileNamePtr = \$_[5]; $$OldFileNamePtr = ""; > > I will be happy if I never have to see a Reference Pointer ever again. > I know, I've been using Perl since circa 1993 and pointers since they came out in Perl 5 (if memory serves). No, we don't have that in Perl 6, explicitly so. -- JJ
