On Fri, Oct 12, 2018 at 5:08 PM ToddAndMargo via perl6-users <
perl6-us...@perl.org> wrote:
> >> On 10/12/18 12:52 PM, Curt Tilmes wrote:
> >> > You could make a subset for the List your're trying to return:
> >> >
> >> > subset liststrint of List where .[0] ~~ Str && .[1] ~~ Int;
> >> > sub RtnOrd( Str $Char --> liststrint) ...
> >>
> >> I am confused.
> >>
> >> I want to get the --> syntax correct for `return $Char, ord($Char)`
>
> On 10/12/18 1:49 PM, Brad Gilbert wrote:
> > That would be `List`
> >
> > sub RtnOrd( Str $Char --> List ){ $Char, ord($Char) }
> > say RtnOrd "A"
> > # (A 65)
>
> $ p6 'sub RtnOrd( Str $Char --> List ){return $Char, ord($Char)}; say
> RtnOrd "A";'
> (A 65)
>
> But "List" does not tell my what is in the list.
>
You can create a brand new type, a subset of Lists where the first element
(we refer to with [0]) is of type Str (~~ Str) and the second element of
the List
(we refer to with [1]) is of type Int (~~ Int).
Define it like this:
subset list-str-int of List where .[0] ~~ Str && .[1] ~~ Int;
then you can say that your routine returns a list that looks like that:
sub RtnOrd( Str $Char --> list-str-int)
