I'm curious about what type of $in is on Proc class. As described in perl6doc: $in, $out and $err are the three standard streams of the to-be-launched program, and default to "-" meaning they inherit the stream from the parent process. Setting one (or more) of them to True makes the stream available as an IO::Pipe object of the same name, like for example $proc.out.
I mean, if $in is IO::Pipe object, how can I pass it True? > my IO::Pipe $bb = True; Type check failed in assignment to $bb; expected IO::Pipe but got Bool (Bool::True) in block <unit> at <unknown file> line 4 I'm interested in the underlying mechanics of it. Please enlighten me. Besides, just curious, why choose '_' as default it looks strange....
