my int16 $x = 0xABCD;
my uint16 $y = $x;
say $x.base(16);
say $y.base(16)
-5433
ABCD
If you just want to coerce to uint16
(my uint16 $ = $x)
say (my uint16 $ = $x).base(16)
On Tue, Jan 7, 2020 at 10:20 AM ToddAndMargo via perl6-users <
perl6-us...@perl.org> wrote:
> On 2020-01-06 22:54, ToddAndMargo via perl6-users wrote:
> > Hi All,
> >
> > What am I doing wrong here?
> >
> > > my int16 $x = 0xABCD;
> > -21555
> >
> > > say $x.base(16);
> > -5433
> >
> > > my uint16 $y = $x.uint16;
> > No such method 'uint16' for invocant of type 'Int'
> > in block <unit> at <unknown file> line 1
> >
> > Many thanks,
> > -T
>
>
> Came up with a work around:
>
> my int16 $x = 0xABCD;
> my uint16 $y = $x +| 0x0000;
> say $x.base(16);
> say $y.base(16)
>
> -5433
> ABCD
>
> What is the proper way?
>
