On Sun, Aug 22, 2021 at 2:58 PM Marc Chantreux <e...@phear.org> wrote:
> so of course i tried
>
> my (@a, @b) = { .[0,2…∞], .[1,3…∞] }.(q<AABBCCDD>.comb);
>
> because i have two lists and two containers. this doesn't work.
> which means @ and $ combines with = to define how things are stored
> but i don't understand how for the moment.
>
Try:
> my (@a, @b) := { .[0,2…∞], .[1,3…∞] }.(q<AABBCCDD>.comb);say @a;say @b
(A B C D)
(A B C D)
In this case the binding operator ':=' makes the difference.
When one uses the assignment operator '=', the right side value is
interpreted as an array of two elements, each one is a list of four
elements: [(A B C D) (A B C D)]. When one binds, each array is bound to one
list.
--
Fernando Santagata
