Re: how do I do a literal string in the target of a regex?

[ToddAndMargo via perl6-users]

On 10/29/22 14:28, ToddAndMargo via perl6-users wrote:

On 10/29/22 13:07, Elizabeth Mattijsen wrote:
 > $ echo "a/b/c/d" | raku -ne 'say .subst("/", Q/\\\/, :g)'
 >

Hi Elizabeth,

Thank you for the subst workaround!

I created a keep of the subst.  Got to
love Raku. 101 ways of doing everything!