"so" will collapse the junction into a Bool.
"say" will append a \n for you, so you don't have to.
On 11 Dec 2023, at 01:52, ToddAndMargo via perl6-users <perl6-us...@perl.org>
wrote:
On 10 Dec 2023, at 21:36, ToddAndMargo via perl6-users <perl6-us...@perl.org>
wrote:
Hi All,
my Str $x="abc3defg"; if $x.contains( "a" || "b" || "3" ) { print "True\n"; } else {
print "False\n" };
True
Is there a way to tell .contains that you want to know
if any of a sequence characters is in a string other that
repeating || over and over. Any [a..z] or [0..9] option?
Many thanks,
-T
On 12/10/23 15:24, Elizabeth Mattijsen wrote:
my @letters = <a b 3>;
if $x.contains(any @letters) {
Hi Elizabeth,
Very interesting. Problem: I was looking for one answer, not many
my $x="abc45def";my @y=<a b c d e f g h i j 1 2 3 4 5>; print $x.contains(any @y) ~
"\n";
True
True
True
True
True
True
False
False
False
False
False
False
False
True
True
On 12/11/23 01:11, Elizabeth Mattijsen wrote:
> my $x="abc45def";
> my @y=<a b c d e f g h i j 1 2 3 4 5>; say so $x.contains(any @y);
Hi Elizabeth,
Awesome! Thank you!
I usually stay away from `say` as in my longer programs, I have found
that when using `say` for debugging, it has been known to print out the
previous value of a variable and not the current value. `print` does
not do this. This is why you see me using `print` so often. And
I can type, so the extra finger motions do not bother me. Capitol
letter also do not for the same reason.
Some tests!
my $x="abc45def"; my @y=<a b c d e f g h i j 1 2 3 4 5>; say so
$x.contains(any @y);
True
my $x="abc45def"; my @y=<g h i j 1 2 3 7 8>; say so $x.contains(any @y);
False
my $x="abc45def"; my @y=<g h i j 1 2 3 4 5>; say so $x.contains(any @y);
True
my $x="abc45def"; my @y=<g h i j 1 2 3 7 8>; say so $x.contains(any @y);
False
Oh now I am really pushing it with these (note the `all` in the
second one)!
my $x="abc45def"; say so $x.contains(any <g h i j 1 2 3 7 8>);
my $x="abc45def"; say so $x.contains(all <g h i j 1 2 3 7 8>);
False
my $x="abc45def"; say so $x.contains(any <a b c d e f g h i j 1 2 3 4 5>);
True
-T
