I'm working on more p6rules unit tests.
Having some trouble. First, understanding when :w means \s* and when it means \s+
Also, these tests are failing when I use :: to separate the modifier from the pattern. But they work when I do ':w blah' (separate with a space). I'm not sure which ways are "right".
The actual failing tests:
my $targ = qq{ foobar baz quux zot\tfum};
p6rule_is ($targ, ':w::baz quux', 'baz\s+quux or baz\s*quux matches'); p6rule_is ($targ, ':w::zot fum', 'zot\s+fum or zot\s*fum matches');
If I remember right Larry's intent was that it depends on word boundaries. Thus the thing to look at is to put "\b" there instead of the "\s+" or "\s*" and see if the match will still work. I.e., if "\b" would succeed then use "\s*" and if "\b" would fail the use "\s+". Thus both of your examples above should use "\s+" because you want to preserve the separation between the words. So, if the rule was
':w::baz ###', then you'd what to use "\s*" as the white space is not needed to keep them separate.
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